Beambb

Data for the analysis of the beam B-B•Column size= 230 230mm•Beams size= 230 500mm overall depth•Slab thickness=150mm•Wall height=(3000-500) =2500mm•Wall thickness=230mm•Unit weight of brick wall= 17.17 kN / m 3•Unit weight of concrete=24kN/m3•Slab Imposed Loading for beam A-ASub-Frame for Beam B- BComputation of second moment of inertia (I)For beamsbd 3 230  5003I=== 239.58 10 7 mm41212For columnsbd 3 230  230 3I=== 23.32  10 7 mm 41212Computation of Relative Stiffnesses (K)K12 = K 23 =I b 239.58 10 7== 75.94 10 4 mm3L3155I b 239.58 10 7K 34 = == 97.79 10 4 mm3L2450K 45 =I b 239.58 10 7== 61.12 10 4 mm3L3920= 3kN/m2and 4kN/m2K 56 =I b 239.58 10 7== 159.72 10 4 mm3L1500K column =I c 23.30  10 7== 7.77  10 4 mm 3L3000Table of K-valuesMemberDepth(mm)230450450Length(mm)300031553155Moment of inertiaColumnBeam 12Beam 23Width(mm)23023023023.32×107239.58×107239.58x107K= IL7.77×10475.94×10475.94x104Beam 342304502450239.58×10797.79x104Beam 452304503920239.58×10761.12x104Beam 562304501500239.58×107159.72x104Distribution Factors (DF):Joint 1Kc=7.77x1041Kb=75.94x104Kc=7.77x104DFEcolumn =DF12 =7.77 x 2= 0.1715.54 + 75.9455.35= 0.8315.54 + 75.94Joint 2Kc=7.77x104Kb=75.94x1042Kb=75.94x104Kc=7.77x104DFEcolumn =DF23 … Purchase document to see full attachment

Related posts:

Houston, Texas, star of hope learning by doing For this assignment you need to undertake research with current